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Post by jefft on Jul 20, 2006 15:33:23 GMT -5
Is there an official explanation/ruling somewhere as to how these type of finishers work exactly?
Take The Betrayer for example. His finishers all work correctly on -
rolls of 2-7 plus or minus opponent's power rating.
Is it based on just the opponent's power rating or the opponent's power rating vs. The Betrayer's?
It seems to be hinting at the former option, however the latter option seems more accurate and realistic.
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Post by Tournament Master on Jul 20, 2006 15:38:49 GMT -5
My assumption is the the 7 baseline already factors in Betrayer's power.
I could see that argument more on the choice charts.
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Post by gatekeeper on Jul 20, 2006 15:45:34 GMT -5
Take The Betrayer for example. His finishers all work correctly on - rolls of 2-7 plus or minus opponent's power rating. Is it based on just the opponent's power rating or the opponent's power rating vs. The Betrayer's? It says 2-7 +/- the OPPONENT'S power rating. So, there it is. I don't see the confusion. The Betrayer's power rating doesn't have anything to do with it. |
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Post by jefft on Jul 20, 2006 15:51:26 GMT -5
Take The Betrayer for example. His finishers all work correctly on - rolls of 2-7 plus or minus opponent's power rating. Is it based on just the opponent's power rating or the opponent's power rating vs. The Betrayer's? It says 2-7 +/- the OPPONENT'S power rating. So, there it is. I don't see the confusion. The Betrayer's power rating doesn't have anything to do with it. Well, that's the way I play it....just thought the other way seemed more accurate. TM's explanation makes it more understandable. |
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Post by gwffantrav on Jul 20, 2006 15:51:31 GMT -5
Yep it's the opponents. Just an example, take Valour. I think his power is a -3 (dont have the cards on hand).
That means if it's a 2-7 +/- Opponent's power rating, you'd just take away 3 from the 7. That means against Valour, it would only work on a roll between 2-4
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